Getting started with Jersey and Spring Boot

Along many new features, Spring Boot 1.2 brings Jersey support. This is great step to attract those developers who like the standard approach as they can now build RESTful APIs using JAX-RS specification and easily deploy it to Tomcat or any other Spring’s Boot supported container. Jersey with Spring platform can play an important role in the development of mico services. In this article I will demonstrate how one can quickly build an application using Spring Boot (including: Spring Data, Spring Test, Spring Security) and Jersey.

Bootstrap a new project

The application is a regular Spring Boot application and it uses Gradle and its latest 2.2 release. Gradle is less verbose than Maven and it is especially great for Spring Boot applications. Gradle can be downloaded from Gradle website:

The initial dependencies to start the project:

dependencies {
    // HSQLDB for embedded database support
    // Utilities
    // AssertJ

The application entry point is a class containing main method and it is annotated with @SpringBootApplication annotation:

public class Application {
    public static void main(String[] args) {, args);

@SpringBootApplication annotation is a convenience annotation that is equivalent to declaring @Configuration, @EnableAutoConfiguration and @ComponentScan and it is new to Spring Boot 1.2.

Jersey Configuration

Getting started can be as easy as creating root resource annotated with @Path and Spring’s @Component:

public class HealthController {
    public Health health() {
        return new Health("Jersey: Up and Running!");

and registering it within a Spring’s @Configuration class that extends from Jersey ResourceConfig:

public class JerseyConfig extends ResourceConfig {
    public JerseyConfig() {

We could launch the application with gradlew bootRun visit: http://localhost:8080/health and we should see the following result:

    "status": "Jersey: Up and Running!"

But it is also possible to write a Spring Boot integration test with fully loaded application context:

@SpringApplicationConfiguration(classes = Application.class)
public class HealthControllerIntegrationTest {

    private RestTemplate restTemplate = new TestRestTemplate();

    public void health() {
        ResponseEntity<Health> entity = 
                restTemplate.getForEntity("http://localhost:9000/health", Health.class);

        assertThat(entity.getBody().getStatus()).isEqualTo("Jersey: Up and Running!");

Jersey 2.x has native Spring support (jersey-spring3) and Spring Boot provides auto-configuration support for it with spring-boot-starter-jersey starter. For more details have a look atJerseyAutoConfiguration class.

Depending on the spring.jersey.type property value either Jersey Servlet or Filter is registered as a Spring Bean:

Mapping servlet: 'jerseyServlet' to [/*]

The default mapping path can be changed via annotation added to ResourceConfig configuration class:

public class JerseyConfig extends ResourceConfig {}

The JSON media type support comes with jersey-media-json-jackson dependency that registers Jackson JSON providers to be used by Jersey.

Spring Data JPA Integration

Spring Data JPA, part of the larger Spring Data family, makes it easy to easily implement JPA based repositories. For those who are not familiar with the project please visit:

Customer and CustomerRepository

Domain model for this sample project is just a Customer with some basic fields:

public class Customer extends AbstractEntity {

    private String firstname, lastname;

    private EmailAddress emailAddress;   

The Customerneeds a @Repository, so we I created a basic one using Spring’s Data repository. Spring Data repositories reduce much of the boilerplate code thanks to a simple interface definition:

public interface CustomerRepository extends PagingAndSortingRepository<Customer, Long> {


With the domain model in place some test data can be handy. The easiest way is to provide a data.sql file with the SQL script to be executed on the application start-up. The file is placed in src/main/resources and it will be automatically picked up by Spring. The script contains several SQL inserts to fill in the customer table. E.g:

insert into customer (id, email, firstname, lastname) values (1, '', 'Joe', 'Doe');

Customer Controller

Having Spring Data JPA repository in place, I created a controller (in terms of JAX-RS - resource) that allows CRUD operations on Customerobject.

Note: I stick to Spring MVC naming conventions for HTTP endpoints, but feel free to call them JAX-RS way.

Get Customers

Let’s start with a method returning all customers:

public class CustomerController {

    private CustomerRepository customerRepository;

    public Iterable<Customer> findAll() {
        return customerRepository.findAll();

Using @Component guarantees CustomerController is a Spring managed object. @Autowired can be easily replaced with standard javax.inject.@Inject annotation.

Since we are using Spring Data in the project I could easily utilize pagination offered by PagingAndSortingRepository. I modified the resource method to support some of the page request parameters:

public Page<Customer> findAll(
        @QueryParam("page") @DefaultValue("0") int page,
        @QueryParam("size") @DefaultValue("20") int size,
        @QueryParam("sort") @DefaultValue("lastname") List<String> sort,
        @QueryParam("direction") @DefaultValue("asc") String direction) {

    return customerRepository.findAll(
            new PageRequest(
                    sort.toArray(new String[0])

To verify the above code I created Spring integration test. In first test I will call for all the records, and based on test data previously prepared I expect to have total 3 customers in 1 page of size 20:

public void returnsAllPages() {
    // act
    ResponseEntity<Page<Customer>> responseEntity = getCustomers(
    Page<Customer> customerPage = responseEntity.getBody();
    // assert

In the second test I will call for page 0 of size 1 and sorting by firstname and sorting direction descending. I expect total elements did not change (3), total pages returned are 3 and content size of the page returned is 1:

public void returnsCustomPage() {

    // act
    ResponseEntity<Page<Customer>> responseEntity = getCustomers(
    // assert
    Page<Customer> customerPage = responseEntity.getBody();


The code can be also checked with curl:

$ curl -i http://localhost:8080/customer

HTTP/1.1 200 OK
Server: Apache-Coyote/1.1
Content-Type: application/json;charset=UTF-8
Content-Length: 702
Date: Sat, 03 Jan 2015 14:27:01 GMT


Please note that for ease of testing the pagination with RestTemplate I created some helper classes: Page, Sort and PageAssertion. You will find them in the source code of the application in Github.

Add New Customer

In this short snippet I used some of the Jersey features like injecting a @Context. In case of creating new entity, we usually want to return a link to the resource in the header. In the below example, I inject UriBuilder into the endpoint class and use it to build a location URI of newly created customer:

private UriInfo uriInfo;

public Response save(Customer customer) {

    customer =;

    URI location = uriInfo.getAbsolutePathBuilder()
            .resolveTemplate("id", customer.getId())

    return Response.created(location).build();

While invoking a POST method (with non existent email):

$ curl -i -X POST -H 'Content-Type:application/json' -d '{"firstname":"Rafal","lastname":"Borowiec","emailAddress":{"value": ""}}' http://localhost:8080/customer

We will get:

HTTP/1.1 201 Created
Server: Apache-Coyote/1.1
Location: http://localhost:8080/customer/4
Content-Length: 0
Date: Sun, 21 Dec 2014 22:49:30 GMT

Naturally, an integration test can be created too. It uses RestTemplate to save the customer with postForLocation method and then retrieve it with getForEntity:

public void savesCustomer() {
    // act
    URI uri = restTemplate.postForLocation("http://localhost:9000/customer",
            new Customer("John", "Doe"));
    // assert
    ResponseEntity<Customer> responseEntity =
            restTemplate.getForEntity(uri, Customer.class);

    Customer customer = responseEntity.getBody();


Update: Integration Testing with Groovy

Integration testing of the API with Groovy and HTTPBuilder module, utilizing JSONSlurper: Groovier Spring Boot Integration Testing

Other methods

The remaining methods of the endpoint are really easy to implement:

public Customer findOne(@PathParam("id") Long id) {
    return customerRepository.findOne(id);

public Response delete(@PathParam("id") Long id) {
    return Response.accepted().build();


Adding Spring Security to the application can be done quickly by adding new dependency to the project:


With Spring Security in classpath application will be secured with basic authentication on all HTTP endpoints. Default username and password can be changed with two following application settings (src/main/resources/

After running the application with Spring Security application we need to provide a valid authentication parameters to each request. With curl we can use --user switch:

$ curl -i --user demo:123 -X GET http://localhost:8080/customer/1

With the addition of Spring Security our previously created tests will fail, so we need to provide username and password parameters to RestTemplate:

private RestTemplate restTemplate = new TestRestTemplate("demo", "123");

Dispatcher Servlet

Spring’s Dispatcher Servlet is registered along with Jersey Servlet and they are both mapped to the root resource. I extendedHealthController and I added Spring MVC request mapping to it:

@RestController // Spring MVC
public class HealthController {

    public Health jersey() {
        return new Health("Jersey: Up and Running!");

    @RequestMapping(value = "/spring-health", produces = "application/json")
    public Health springMvc() {
        return new Health("Spring MVC: Up and Running!");

With the above code I expected to have both health and spring-health endpoints available in the root context but apparently it did not work. I tried several configuration options, including setting spring.jersey.filter.order but with no success.

The only solution I found was to either change Jersey @ApplicationPath or to change Spring MVC server.servlet-path property:


In the latter example calling:

$ curl -i --user demo:123 -X GET http://localhost:8080/s/spring-health

returned expected result:

    "status":"Spring MVC: Up and Running!"

Use Undertow instead of Tomcat

As of Spring Boot 1.2 Undertow lightweight and performant Servlet 3.1 container is supported. In order to use Undertow instead of Tomcat, Tomcat dependencies must be exchanged with Undertow ones:

buildscript {
    configurations {
        compile.exclude module: "spring-boot-starter-tomcat"

dependencies {

When running the application the log will contain:

org.xnio: XNIO version 3.3.0.Final
org.xnio.nio: XNIO NIO Implementation Version 3.3.0.Final
Started Application in 4.857 seconds (JVM running for 5.245)


In this blog post I demonstrated a simple example how to get started with Spring Boot and Jersey. Thanks to Jersey auto-configuration adding JAX-RS support to Spring application is extremely easy.

In general, Spring Boot 1.2 makes building applications with Java EE easier: JTA transactions using either an Atomikos or Bitronix embedded transaction manager, JNDI Lookups for both DataSource and JMS ConnectionFactory in JEE Application Server and easier JMS configuration.


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